A small heating coil has a constant resistance of 25 W. a) How much power would the coil consume if the voltage drop across it is 96 V?
- Anonymous2 months ago
25 W is not a resistance.
You need to learn some electrical terminology before coming here to ask a question.
- 2 months ago
resistance is measured in Ohms,
Not Watts.If you meant Ohms, IE the coil has 25 Ohms resistancethem power expended in the coil is given by Power = V x Ior V^2 / R= 368.64 Watts
- JimLv 72 months ago
The "units" are extremely important. Did you mean 'ohms'??
IF ohms, then:
I = V/R and Watts = I*V So Watts = V²/R
W = (96)²/25 = 368.64 w, but I would round to 370 w
- charlatanLv 72 months ago
how tall am i, if i am 5'6"
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- PhilomelLv 72 months ago
The resistance is 25w/96v=.260Ω
It will use 25W.
If the coil is 25Ω the the power will be 96^2/25= 387 W.
- 異域秦後人Lv 72 months ago
AS YOU MARKED ON QUESTION ------->>> 25W !!!
- micatkieLv 72 months ago
The resistance should "25 Ω" instead of "25 W".
Power of the coil consumed
= 370 W (to 2 sig. fig.)