Chemistry?

Question

Help please !!! Thank you!

Answer 1

Favourite answer

4.a.

(25.0 g N2) / (28.01344 g N2/mol) = 0.892 mol N2

b.

(25.0 g N2) / (28.01344 g N2/mol) × (22.414 L/mol) = 20.0 L N2

c.

(25.0 g N2) / (28.01344 g N2/mol)  × (6.022 × 10^23 molecules/mol) =

5.37 × 10^23 molecules N2

d.

(25.0 g N2) / (28.01344 g N2/mol)  × (6.022 × 10^23 molecules/mol) x

(2 atoms N / 1 molecule N2) = 1.07 × 10^24 atoms N

Answer 2

From your other questions, you should be able to do these on your own.

a. Divide 25.0 g by the molar mass of N2.

b, c and d. See your other questions for the rest.