Chemistry?

Help please !!! Thank you!

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  • 5 months ago
    Favourite answer

    4.a.

    (25.0 g N2) / (28.01344 g N2/mol) = 0.892 mol N2

    b.

    (25.0 g N2) / (28.01344 g N2/mol) × (22.414 L/mol) = 20.0 L N2

    c.

    (25.0 g N2) / (28.01344 g N2/mol)  × (6.022 × 10^23 molecules/mol) =

    5.37 × 10^23 molecules N2

    d.

    (25.0 g N2) / (28.01344 g N2/mol)  × (6.022 × 10^23 molecules/mol) x

    (2 atoms N / 1 molecule N2) = 1.07 × 10^24 atoms N

  • 5 months ago

    From your other questions, you should be able to do these on your own.

    a. Divide 25.0 g by the molar mass of N2.

    b, c and d. See your other questions for the rest.

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