Anonymous
Anonymous asked in Science & MathematicsMathematics · 2 months ago

What is the solution of the differential equation y'= -2y?

2 Answers

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  • 2 months ago
    Favourite answer

    The general solution is y = C e^(-2x)

  • 2 months ago

    dy/dx = -2y

    so, ∫ (1/y) = -2 ∫ dx

    => lny = -2x + lnC

    so, lny - lnC = -2x

    => ln(y/C) = -2x

    Then, y/C = e⁻²ˣ

    Therefore, y = C​e⁻²ˣ

    :)>

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