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# Value of the equilibrium constant? ?

Two reactions and their equilibrium constants are given.

A+2B2C↽−−⇀2C↽−−⇀D𝐾1𝐾2=2.69=0.276

Calculate the value of the equilibrium constant for the reaction D↽−−⇀A+2B.

### 1 Answer

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- micatkieLv 76 months agoFavourite answer
Method 1:

A + 2B ⇌ 2C K₁ = 2.69

2C ⇌ D K₂ = 0.276

Add the above 2 equations, and cancel 2C on the both sides:

A + 2B ⇌ D K₃ = K₁K₂

Reverse the above equation:

D ⇌ A + 2B K = 1/K₃

K = 1/K₃ = 1/(K₁K₂) = 1/(2.69 × 0.276) = 1.35

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Method 2:

A + 2B ⇌ 2C K₁ = [C]²/([A][B]²) = 2.69

2C ⇌ D K₂ = [D]/[C]² = 0.276

D ⇌ A + 2B K = ?

K = [A][B]²/[D]

= ([A][B]²/[C]²) × ([C]²/[D])

= (1/K₁) × (1/K₂)

= (1/2.69) × (1/0.276)

= 1.35

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