Find the balanced redox reaction of Bi3+ + OH- + MnO4                MnO2 + BiO3-?

2 Answers

Relevance
  • 1 month ago

    "MnO₄" does not exist. It should be "MnO₄⁻" instead.

    Oxidation half equation: Bi³⁺ + 6OH⁻ → BiO₃⁻ + 3H₂O + 2e⁻

    Reduction half equation: MnO₄⁻ + 2H₂O + 3e → MnO₂ + 4OH⁻

    (Oxidation half equation)×3 + (Reduction half equation)×2, and cancel 6e⁻, 8OH⁻ and 4H₂O on the both sides. The balanced overall redox equation is:

    3Bi³⁺ + 10OH⁻ + 2MnO₄⁻ → 3BiO₃⁻ + 2MnO₂ + 5H₂O

  • 1 month ago

    Half-reactions:

    Bi^3+ ---> BiO3^-

    MnO4^- ---> MnO2

    Balance in acidic solution:

    3H2O + Bi^3+ ---> BiO3^- + 6H^+ + 2e^-

    3e^- + 4H^+ + MnO4^- ---> MnO2 + 2H2O

    Equalize electrons:

    9H2O + 3Bi^3+ ---> 3BiO3^- + 18H^+ + 6e^-

    6e^- + 8H^+ + 2MnO4^- ---> 2MnO2 + 4H2O

    Add and eliminate like items:

    5H2O + 3Bi^3+ + 2MnO4^- ---> 3BiO3^- + 2MnO2 + 10H^+

    Change to basic solution:

    10OH^- + 5H2O + 3Bi^3+ + 2MnO4^- ---> 3BiO3^- + 2MnO2 + 10H2O

    Remove water:

    10OH^- + 3Bi^3+ + 2MnO4^- ---> 3BiO3^- + 2MnO2 + 5H2O

    More examples:

    https://www.chemteam.info/Redox/Balance-Redox-Base...

Still have questions? Get answers by asking now.