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# if p(-.6, -.8) is a point on the unit circle in the figure above, what is the exact value of tan(theta)+sin(theta)?

The circle is in the details. thanks

### 3 Answers

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- MichaelLv 71 month ago
opp = y = -0.8

adj = x = -0.6

hyp = 1 ( since it's a unit circle)

Tan 𝜽 = opp/adj

Tan 𝜽 = (-0.8) / (-0.6)

Tan 𝜽 = 4/3 <–––––

Sin 𝜽 = opp/ hyp

Sin 𝜽 = -0.8 / 1

Sin 𝜽 = -4/5

Tan 𝜽 + Sin 𝜽 = 4/3 - 4/5

Tan 𝜽 + Sin 𝜽 = 20/15- 12/15

Tan 𝜽 + Sin 𝜽 = 8/15 <–––––

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