Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

Physics help please?!?

The gravitational force between two people is 6.5x10^-7 N. If the first person mass decreased by 1/3 and the second persons mass increased by 4/3 and the distance between them increased by a factor of three what would the gravitational force be??

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  • Anonymous
    1 month ago

     F = 6.5*10^-7*2/3*4/3/3^2 = 6.4*10^-8 N 

  • NCS
    Lv 7
    1 month ago

    F = G*m*M / d²

    where m = mass of first person

    and M = mass of second person

    and d is the initial distance between them

    F' = G*m'*M' / d'²

    m' = (1 - 1/3)m = 2m/3

    M' = (1 + 4/3)M = 7M/3

    d' = 3d

    so

    F' = G*(2/3)m*(7/3)M / (3d)² = (G*m*M/d²) * (14/81) = F*14/81

    so for your F,

    F' = 1.1e-7 N

    UNLESS "increased by 4/3" means that

    M' = 4M/3

    (which would be incredibly poor wording), then

    F' = F * 8/81

    and so

    F' = 6.4e-6 N

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