Anonymous

# Physics help please?!?

The gravitational force between two people is 6.5x10^-7 N. If the first person mass decreased by 1/3 and the second persons mass increased by 4/3 and the distance between them increased by a factor of three what would the gravitational force be??

### 2 Answers

Relevance

- Anonymous1 month ago
F = 6.5*10^-7*2/3*4/3/3^2 = 6.4*10^-8 N

- NCSLv 71 month ago
F = G*m*M / d²

where m = mass of first person

and M = mass of second person

and d is the initial distance between them

F' = G*m'*M' / d'²

m' = (1 - 1/3)m = 2m/3

M' = (1 + 4/3)M = 7M/3

d' = 3d

so

F' = G*(2/3)m*(7/3)M / (3d)² = (G*m*M/d²) * (14/81) = F*14/81

so for your F,

F' = 1.1e-7 N

UNLESS "increased by 4/3" means that

M' = 4M/3

(which would be incredibly poor wording), then

F' = F * 8/81

and so

F' = 6.4e-6 N

If you find this helpful, please select Favorite Answer!

Still have questions? Get answers by asking now.