physics electric charges and fields?
An electron a proton fall from rest in a uniform electric field 3×10^4 N/c. electrom takes 3×10^-9 s and proton takes 1×10^-7 compare the distance of the fall
- NCSLv 71 month ago
both have charge magnitude
|q| = 1.6e-19 C
and so both experience a force of
|F| = |q| * E = 4.8e-15 N
d = ½at² = ½(F/m)*t² = ½(4.8e-15N / 9.11e-31kg)*(3e-9s)²
d = 2.37e-3 m ≈ 2 cm
D = ½(4.8e-15N / 1.67e-27kg)(3e-9s)²
D = 1.29e-5 m ≈ 13 µm
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