“a” and “b” are 128 mi apart. car leaving a averages 10mi/h more than the other car leaving “b”. they meet aftr 1hr36mins.what is ave speed?

Update:

the car leaving a and b both left at the same time. what is the average speeds of the cars?

1 Answer

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  • Let's call them Car A and Car B.  In 1 hr 36 minutes, they close a distance of 128 miles.

    distance = velocity * time

    128 = (A + B) * (1 + 36/60)

    A = 10 + B

    128 = (10 + B + B) * (1 + 0.6)

    128 = (10 + 2B) * 1.6

    80 = 10 + 2B

    70 = 2B

    35 = B

    B travels at 35 mph

    A travels at 45 mph

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