Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

the zeros of a quadratic function are 4 and -3, if the graph of the function has a y int of 48, what is the quadratic?

3 Answers

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  • ted s
    Lv 7
    1 month ago

    y = A ( x + 3 ) ( x - 4) where A = 48 / ((3)(4))

  • Bryce
    Lv 7
    1 month ago

    y= -4(x - 4)(x + 3)

  • 1 month ago

    Write down the two zeros:

    x = 4

    x = -3

    Rewrite them as expressions equal to zero:x - 4 = 0

    x + 3 = 0

    Multiply those expressions together:

    y = (x - 4)(x + 3)

    You can also multiply that by any non-zero constant and it will have the same zeros:

    y = a(x - 4)(x + 3)

    Expand that:

    y = a(x² - x - 12)

    y = ax² - ax - 12a

    The y-intercept is found by setting x=0:

    y-int = -12a

    And you want that equal to 48:

    -12a = 48

    a = 48/-12

    a = -4

    Write the final quadratic:

    y = -4x² + 4x + 48

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