Anonymous
Anonymous asked in Science & MathematicsMathematics · 4 weeks ago

How do I solve this problem?   Two more than a certain number is less than the product of 7/8 and the number.?

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• Anonymous
2 weeks ago

The length of the rectangle is 3.5 inches more than its width. The perimeter of the rectangle is 31 inches. Find the length and width of the rectangle.

• 4 weeks ago

I would probably use algebra.

Call the number "x"

x + 2 < (7/8) x

Subtract x from both sides

2 < (7/8)x -x

2 < -(1/8)x

Multiply both sides by -8 (this includes changing the "less than" direction)

-16 >= x

That's the solution."X" can be any number smaller than -16. You should test it with x = -17, -16, and -15.

• 4 weeks ago

Let x be the number.

Write an inequality representing the statement.

"Two more than a certain number..."

x + 2

"...is less than..."

x + 2 <

"...the product of 7/8 and the number"

x + 2 < (7/8)x

Start by subtracting (7/8)x from both sides:

x - (7/8)x + 2 < 0

Subtract 2 from both sides:

x - (7/8)x < -2

Combine the like terms:

(8/8)x - (7/8)x < -2

(1/8)x < -2

Multiply both sides by 8. It's a positive number so you don't change the inequality symbols:

x < -16