# How do I solve this problem? Two more than a certain number is less than the product of 7/8 and the number.?

### 3 Answers

- Anonymous2 weeks ago
Can anyone please help me set up an equation for this question with steps to solve?

The length of the rectangle is 3.5 inches more than its width. The perimeter of the rectangle is 31 inches. Find the length and width of the rectangle.

- MorningfoxLv 74 weeks ago
I would probably use algebra.

Call the number "x"

x + 2 < (7/8) x

Subtract x from both sides

2 < (7/8)x -x

2 < -(1/8)x

Multiply both sides by -8 (this includes changing the "less than" direction)

-16 >= x

That's the solution."X" can be any number smaller than -16. You should test it with x = -17, -16, and -15.

- PuzzlingLv 74 weeks ago
Let x be the number.

Write an inequality representing the statement.

"Two more than a certain number..."

x + 2

"...is less than..."

x + 2 <

"...the product of 7/8 and the number"

x + 2 < (7/8)x

Start by subtracting (7/8)x from both sides:

x - (7/8)x + 2 < 0

Subtract 2 from both sides:

x - (7/8)x < -2

Combine the like terms:

(8/8)x - (7/8)x < -2

(1/8)x < -2

Multiply both sides by 8. It's a positive number so you don't change the inequality symbols:

x < -16