Find the equation of a line that goes through (-3,4) and (6,1).?
Write in slope intercept form
- 4 weeks ago
Slope intercept is y=mx+b, where m is the slope and b is the y-intercept.
The slope (m) = (y2-y1)/(x2-x1). Any point can be (x1,y1) or (x2,y2). Let's make (6,1) the (x2,y2) point and (-3,4) the (x1,y1) point.
m = (1-4)/(6-(-3)) = -3/9 = -1/3
to find b, the y-int, use any point and the slope we found and plug it into the equation.
1 = (-1/3)*6 + b
1 = -2 + b
3 = b
Thus our final equation is y = (-1/3)x+3