Find the equation of a line that goes through (-2,-4) and is perpendicular to y=2/3x-5?

Write in slope intercept form 

2 Answers

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  • 1 month ago

    In order for two lines to be perpendicular, the product of their slopes must be equal to -1. 

    Thus the slope of this perpendicular line, m, is:

    (2/3) * m = -1

    m = -3/2

    now plug this slope and the point we're given into the equation y=mx+b

    -4 = (-3/2)*-2+b

    -4 = 3 + b

    -7 = b

    then we know the answer is y = -3/2x-7

  • rotchm
    Lv 7
    1 month ago

    Hint:

    Given y = mx + b. What is the slope of this line?

    Then, what is therefore the slope M of the perpendicular of m ?

    Answer these and we will take it from there. 

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