Find the equation of a line that goes through (-2,-4) and is perpendicular to y=2/3x-5?
Write in slope intercept form
- 1 month ago
In order for two lines to be perpendicular, the product of their slopes must be equal to -1.
Thus the slope of this perpendicular line, m, is:
(2/3) * m = -1
m = -3/2
now plug this slope and the point we're given into the equation y=mx+b
-4 = (-3/2)*-2+b
-4 = 3 + b
-7 = b
then we know the answer is y = -3/2x-7
- rotchmLv 71 month ago
Given y = mx + b. What is the slope of this line?
Then, what is therefore the slope M of the perpendicular of m ?
Answer these and we will take it from there.