Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

Chemistry help part 2!?

In a calibration experiment, a 1.04 millimole sample of Na2CO3 gave 0.82 millimoles of CO2 gas. If a 0.346 g of pure Na2CO3 was reacted with excess acid, what volume of gas will be measured on this apparatus (in Litres at STP)? (Hint: Start by calculating the percent yield)

1 Answer

Relevance
  • david
    Lv 7
    1 month ago

    In a calibration experiment, a 1.04 millimole sample of Na2CO3 gave 0.82 millimoles of CO2 gas. If a 0.346 g of pure Na2CO3 was reacted with excess acid, what volume of gas will be measured on this apparatus 

     = = = = the wording makes these sound like 2 unrelated problems.

       0.346 g of pure Na2CO3 was reacted with excess acid, what volume of gas will be measured

       0.346/106  =  0.003264 mol CO2 produced

     0.82 / 1.04  X 100  =  78.846% yield

       0.003264 X 0.78846  =  0.002573538 mmol

      vol. calculations require pressure and temp. but neither is given == assume STP??

        

      

Still have questions? Get answers by asking now.