Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

Maths (Word Simultaneous Equations)?

A year ago, a father was four times as old as his son. Three years ago, he was five times as old as his son. Find the age of the father and the son now. 

3 Answers

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  • 1 month ago

    (f - 1) = 4(s - 1)

    (f - 3) = 5(s - 3)

    4s - f = 3

    5s - f = 12

    s = 9

    f = 33

    Now the father is 33 years old

    and the son is 9 years old.

  • 1 month ago

    Let the ages now of the father and son be f and s.

    so, f - 1 = 4(s - 1)

    => f - 4s = -3...(1)

    f - 3 = 5(s - 3)

    => f - 5s = -12...(2)

    (1) - (2) => s = 9

    so, f = 33

    Then, father is 33 now and son is 9

    Check, one year ago they are 32 and 8

    Three years ago they are 30 and 6

    :)>

  • 1 month ago

    Father is 33. Son is 9. 

    One year ago, father is 32 and son is 8, so father is 4 times as old as the son. 

    Three years ago, father is 30 and son is 6 so father is 5 times as old as the son. 

    You’re welcome. 

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