Physics Soccer Ball?
Suppose a soccer player kicks the ball from a distance 27.0 m toward the goal. Find the initial speed of the ball if it just passes over the goal, 2.4 m above the ground, given the initial direction to be 38.0° above the horizontal.
- NCSLv 74 weeks agoFavourite answer
Easiest is the trajectory equation:
y = h + x*tanΘ - gx² / (2v²cos²Θ)
y = height at range of interest = 2.4 m
h = initial height = 0 m
x = range of interest = 27.0 m
v = launch velocity = ???
Θ = launch direction = 38.0º
2.4 = 0 + 27.0*tan38.0º - 9.81*27.0² / (2v²cos²38.0º)
v = 17.6 m/s
Hope this helps!Source(s): Please revisit this working: https://answers.yahoo.com/question/index?qid=20201...