# Given the function... y = (x-2)^2 graphed in the image,?

Algebra Problem.

Relevance
• Anonymous
1 month ago

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• 1 month ago

You need to restrict the domain so that you don't end up with two values at the same height (y-value). In a parabola, every horizontal line that crosses the graph goes through the function twice (except for the vertex). So you need to get rid of half of the parabola.

Most often that is done by keeping the vertex and every point to the *right*.

Domain: x ≥ 2

When you do that, you end up with a function which has an inverse.

• Ian H
Lv 7
1 month ago

1. This explanation about domain and range is easy to understand.

https://www.math.net/domain-and-range

2. This is graph of the inverse of y = (x – 2)^2

https://www.wolframalpha.com/input/?i=y+%3D+2+%2B+...

3. What restriction on the domain of y = (x – 2)^2 would result in the inverse being a function, (as described in 1)?