X varies inversely as y^2 and x=6 when y=8. Find x when y=2?

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  • 3 months ago

    X varies inversely as y^2

    so x = k/y^2 for some constant k.

    x=6 when y=8

    Substitute those values in x = k/y^2  and solve for k to figue out what k is.

    Substitute y = 2 and the k value you found in x = k/y^2 to find x.

  • 3 months ago

    x = ky²

    plug in the numbers to find k

    6 =  k8²

    k = 6/64 = 3/32

    therefore eq is x = (3/32)y²

    x(2) = (3/32)(2)² = (3/32)8 = 3/4

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