X varies inversely as y^2 and x=6 when y=8. Find x when y=2?

Answer 1

X varies inversely as y^2

so x = k/y^2 for some constant k.

x=6 when y=8

Substitute those values in x = k/y^2  and solve for k to figue out what k is.

Substitute y = 2 and the k value you found in x = k/y^2 to find x.

Answer 2

x = ky²

plug in the numbers to find k

6 =  k8²

k = 6/64 = 3/32

therefore eq is x = (3/32)y²

x(2) = (3/32)(2)² = (3/32)8 = 3/4