Distance traveled from 0 - 100?

If car accelerates from 0 - 100 km/h in 10 seconds and if acceleration is rising at the same rate, how far would a car travel before reaching 100 km/h? So if at 1 second it is at 10 km/h at 2 seconds 20 km/h and so on.. having 1 km/h added with every second.

Update:

Correction, "having 10 km/h added with every second."

3 Answers

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  • JJ
    Lv 7
    4 weeks ago
    Favourite answer

    There's no need for graphs and formulas, this one is a no-brainer:

    At 100 kph the car travels about 27.7778 meters per second. 

    so... 27.7778 meters/sec * 10 sec = 277.778 meters

    Since the acceleration was linear, simply cut that in half... 138.889 meters

  • Dixon
    Lv 7
    4 weeks ago

    Sketch the time versus velocity, graph and the distance is the area of the triangle.

    Convert numbers to common units, eg km and hours.

    distance = (1/2)(10/(60 x 60)) x 100 

    distance = 0.139 km

    distance = 139 m

    This is also one of the constant acceleration suvat equations,

    d = (1/2)(u + v)t

    Attachment image
  • 4 weeks ago

    RE: ". . . and if acceleration is rising at the same rate . . ."

    and

    RE: ". . . having 10 km/h added with every second."

    No, the acceleration is not increasing, the velocity is increasing.

    That's what acceleration is, a change in velocity

    a = acceleration = 10 km/h/s = 2.7777778 m/s

    v0 = initial velocity = 0 km/h = 0.0 m/s

    v = final velocity = 100 km/h = 27.777778 m/s

    Δx = distance = to be determined

    v² = (v0)² + 2aΔx

    v² - (v0)² = 2aΔx

    [v² - (v0)²] / 2a = Δx

    Δx = [v² - (v0)²] / 2a

    Δx = [27.78 m/s)² - (0.0 m/s)²] / 2(2.778 m/s²)

    Δx = 138.88889 m ≈ 139 m

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