Anonymous
Anonymous asked in Science & MathematicsPhysics · 4 weeks ago

What is the coefficient of friction between the surface and the box?

A 44.3kg box is sliding down a 40.0 degrees incline. If the acceleration of the box is 0.250m/s^2, what is the coefficient of friction between the surface and the box?

1 Answer

Relevance
  • 4 weeks ago
    Favourite answer

    F = ma = 44.3 kg x 0.25 m/s² = 177.2 N

    weight = 44.3 kg x 9.8 N/kg = 434.14

    component of that parallel to surface is 434.14 sin 40 = 279 N, this causes a force down the slope. This force minus friction causes acceleration.

    component of that normal to surface is 434.14 cos 40 = 332.6 N, this causes a force of friction.

    net force down the slope = 279 – µ332.6 = 177.2

    µ332.6 = 101.8

    µ = 0.306

Still have questions? Get answers by asking now.