Anonymous
Anonymous asked in Science & MathematicsPhysics · 2 months ago

If something is traveling at constant acceleration of +14.9 m/s^2. How long will it take to reach an intercept velocity of +390.7 m/s?

Can some tell me the equation to use for this question? 

5 Answers

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  • 2 months ago

    390.7/14.9=26.22 Seconds........................

  • 2 months ago

    The equation IS THE ANSWER.  Actually reducing it to numbers is a waste of time.

  • 2 months ago

    In 1 second, it gains 14.9 m/s.

    In 2 seconds, it gains 2 * 14.9 m/s.

    In 3 seconds, it gains 3 * 14.9 m/s.

    Do you see a pattern here?

    In "x" seconds it gains x * 14.9 m/s. Just solve the equation x * 14.9 = 390.7.

  • oubaas
    Lv 7
    2 months ago

    for stretching the same space

    397t = 14.9/2*t^2

    14.9t = 397*2 

    t =  2V/a = 397*2 /14.9 = 53.28 sec 

    for getting the same speed

    t' = V/a = t/2 = 26.64 sec 

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  • Jim
    Lv 7
    2 months ago

    𝑣 = a*t + 𝑣₀

    To achieve 390.7 m/s:

    390.7 = 14.9 * t

    t = 26.221476510067114093959731543624 s

    Now round to 3 sigfigs: 26.2 s

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