The diameter of a cylindrical construction pipe is 6ft. If the pipe is 27ft long, what is its volume?

6 Answers

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  • 2 weeks ago

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  • John
    Lv 5
    1 month ago

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  • 2 months ago

    If it is a cylinder with an ID of 6 ft.

    V= 2 pi R^2 L=6.28*3^2*27=1,526.814 cu ft.=1421.4 Gal

  • 2 months ago

    You failed to define the wall thickness of the pipe or if the 6 ft diameter is inside or outside diameter. Pipes of a nominal 6 ft size can be either

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  • Jim
    Lv 7
    2 months ago

    Volume = cross-sectional Area times Length

    V = (𝞹r²) * L

    V = 𝞹(3²) * 27 ft³ = 763.4ft³

    or since 1 gallon = 231in³, then 5711 gallons

  • Ray J
    Lv 7
    2 months ago

    Somewhere between quite a bit and  sh*t ton.

    Actually 3 x 3 x pi x 27

    763.4 cubic feet

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