I got part 1 wrong?

My limits were incorrect. I got my upper and lower limits as 2 and 546 by plugging in 25 and 9 to 627-r^2

What would be the indefinite integral and in terms of u?

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2 Answers

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  • Anonymous
    1 month ago

    another homework cheater

  • Ash
    Lv 7
    2 months ago

    Your limits are correct. Maybe its the way you wrote the function. Try writing as below

    = ₅₄₆∫² -½(√u) du

    Next find antiderivative but do not substitute the limits

    = -½ ₅₄₆∫² (u^½) du

    = [-½ * u^(½+1) / ((½+1)]  ₅₄₆|²

    = [-½ * ⅔ u^(3/2)]   ₅₄₆|²

    = [-⅓√u³] ₅₄₆|²

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