# I got part 1 wrong?

My limits were incorrect. I got my upper and lower limits as 2 and 546 by plugging in 25 and 9 to 627-r^2

What would be the indefinite integral and in terms of u?

### 2 Answers

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- Anonymous1 month ago
another homework cheater

- AshLv 72 months ago
Your limits are correct. Maybe its the way you wrote the function. Try writing as below

= ₅₄₆∫² -½(√u) du

Next find antiderivative but do not substitute the limits

= -½ ₅₄₆∫² (u^½) du

= [-½ * u^(½+1) / ((½+1)] ₅₄₆|²

= [-½ * ⅔ u^(3/2)] ₅₄₆|²

= [-⅓√u³] ₅₄₆|²

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