Calculate the magnitude of the force acting on a charge 6Coulombs due to a charge of 19Coulombs at a distance of 15m away from it...?
The force constant k is 9E9 [1/(Farad/m)]. Give your answer in GN where 1 GN = 1E9 Newtons
please show step by step solution.
- billrussell42Lv 72 months agoFavourite answer
F = (9e9)(6)(19) / 15² = ___ N
F = (9)(6)(19) / 225 = ___ GN
Coulomb's law, force of attraction/repulsionF = kQ₁Q₂/r² Q₁ and Q₂ are the charges in coulombs F is force in newtons r is separation in meters k = 8.99e9 Nm²/C²