Anonymous
Anonymous asked in Science & MathematicsChemistry · 2 months ago

What mass of helium gas is present in a 11.1-L sample of this mixture at 283 K ?

A gas mixture with a total pressure of 760 mmHg contains each of the following gases at the indicated partial pressures: 123 mmHg CO2, 221 mmHg Ar, and 179 mmHg O2. The mixture also contains helium gas.

Partial pressure of helium gas is 237 mmHg.

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  • 2 months ago

    (760 mmHg total) - (123 mmHg CO2) - (221 mmHg Ar) - (179 mmHg O2) =

    237 mmHg He

    n = PV /  RT = (237 mmHg) x (11.1 L) / ((62.36367 L mmHg/K mol) x (283 K)) =

    0.1491 mol He

    (0.1491 mol He) x (4.0026 g He/mol) = 0.597 g He

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