A capacitor with air between its plates has capacitance 5 µF. What is its capacitance when dry wax of dielectric constant 2.7 is placed between the plates?
- az_lenderLv 71 month ago
The dielectric constant simply multiplies
C = (epsilon-naught)A/d
by a factor of Kappa, the dielectric constant.
So the answer to your problem is
(5 uF)*2.7 = 13.5 uF.