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I really need help with this calculus related question?

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  • rotchm
    Lv 7
    2 weeks ago

    Consider all vectors (a,b,c) perpendicular to L2. Thus,

    (1,4,-1) • (a,b,c) = 0.

    The point  of  L1 minus (1,13,-3) is such a sought vector.

    That is, (-2+s, 1+4s, 0-s) - (1,13,-3) is your (a,b,c).

    Plug, solve for s. You have your point of L1.

    Done!

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