Yahoo Answers: Answers and Comments for An electron moving along the x axis has a position given by x = 14te4t m,? [Physics]
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From bryan_thegoalie
enAU
Sat, 24 Sep 2011 08:48:54 +0000
3
Yahoo Answers: Answers and Comments for An electron moving along the x axis has a position given by x = 14te4t m,? [Physics]
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From kuiperbelt2003: the phrase momentarily stops means you want to...
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https://au.answers.yahoo.com/question/index?qid=20110924084854AAubpEp
Sat, 24 Sep 2011 09:00:05 +0000
the phrase momentarily stops means you want to find when and where the velocity is zero, to do this, we differentiate x(t) and find where this is zero (in other words, find the extremum of the x function)
v = dx/dt = 14 e^4t  56t e^4t =0
14 e^14t = 56t e^4t
the common exponential factors cancel, and we find easilty that t=1/4s
this is the time of zero velocity; substitute t=1/4 into the x(t) equation to find:
x(t=1/4) = (14/4)e^(1)

From ascencio: right here we pass, x=3t^4 16t^3+24t^2 a. Dif...
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Sat, 22 Oct 2016 11:00:40 +0000
right here we pass, x=3t^4 16t^3+24t^2 a. Differentiate each and each and every area by technique of t, speed, dx/dt = 12 t^3  40 8 t^2 + 40 8 t  (a million) Acceleration, d^2x/dt^2 = 36 t^2  ninety six t + 40 8  (2) b. right here V = 0; from 1st eqn, 0 = 12 t^3  40 8 t^2 + 40 8 t so t = 0 or 2 s c. at t = 0 (right here it will be both at 0 or 2 or both, yet by technique of utilising some values we may be able to be certain it will be 0) d. right here evaluate eqn 2 = 0; that provides t = 2/3 or 2. considering the fact that 2/3 < 2, evaluate the occation even as t = 2/3, then practice that value to eqn a million, to get the answer, V = 128/9 (i.e. 14.22 m/s).