Yahoo Answers: Answers and Comments for Simplify this maths problem? [Mathematics]
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From Hadleigh
enAU
Wed, 21 Aug 2019 21:11:54 +0000
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Yahoo Answers: Answers and Comments for Simplify this maths problem? [Mathematics]
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From JOHN: Answer
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Thu, 22 Aug 2019 07:40:01 +0000
Answer

From sepia: (3/y)^4 (1/5 y^4)^2
= 81y^8 / (25 y^4)
= 81y^...
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Wed, 21 Aug 2019 23:31:40 +0000
(3/y)^4 (1/5 y^4)^2
= 81y^8 / (25 y^4)
= 81y^4 / 25

From Pinkgreen: [(3/y)^4][(y^4)/5]^2
=
[81/y^4][(y^8)/25]
=
(...
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Wed, 21 Aug 2019 22:06:39 +0000
[(3/y)^4][(y^4)/5]^2
=
[81/y^4][(y^8)/25]
=
(81y^4)/25

From Krishnamurthy: (3/y)^4(1/5 y^4)^2
= (81/y^4)(y^8/25)
= 81y^4/25
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Wed, 21 Aug 2019 21:59:01 +0000
(3/y)^4(1/5 y^4)^2
= (81/y^4)(y^8/25)
= 81y^4/25

From llaffer: First, keep fractions as fractions.
Then your...
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Wed, 21 Aug 2019 21:27:58 +0000
First, keep fractions as fractions.
Then your y's can be combined from the first factor and the second factor.
You started correctly, but needed to finish things up.

From Lôn: Do each separately first....
(81/y^4) x (y^8/...
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Wed, 21 Aug 2019 21:16:25 +0000
Do each separately first....
(81/y^4) x (y^8/25) ......now multiply
81y^8 / 25y^4
(81y^4)/25

From Ocate: y8/y⁴ (81/25 ) = y ^(84) * 81/25
=81/25 y⁴
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Thu, 22 Aug 2019 18:03:37 +0000
y8/y⁴ (81/25 ) = y ^(84) * 81/25
=81/25 y⁴

From Como: 
( 18/y^4 ) x (y^8/25)
( 18/25 ) y^4
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Thu, 22 Aug 2019 20:42:33 +0000

( 18/y^4 ) x (y^8/25)
( 18/25 ) y^4

From Jim Moor: 81/y^4 (0.04y^8) is ok as far as it goes, but...
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Wed, 21 Aug 2019 22:42:27 +0000
81/y^4 (0.04y^8) is ok as far as it goes, but it could go further
81/y^4 * y^8 / 25
81/25 y⁴