Yahoo Answers: Answers and Comments for Math Help Please? [Mathematics]
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From Hello2098
enAU
Tue, 22 Oct 2019 00:00:38 +0000
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Yahoo Answers: Answers and Comments for Math Help Please? [Mathematics]
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https://au.answers.yahoo.com/question/index?qid=20191022000038AA9EPLH
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From sepia: (2x^2  5x + 1)(3x  1)
= 6x^3  17x^2 + 8x  1
https://au.answers.yahoo.com/question/index?qid=20191022000038AA9EPLH
https://au.answers.yahoo.com/question/index?qid=20191022000038AA9EPLH
Tue, 22 Oct 2019 05:20:11 +0000
(2x^2  5x + 1)(3x  1)
= 6x^3  17x^2 + 8x  1

From Iggy Rocko: Use the distributive property.
(2x^2  5x + 1)...
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https://au.answers.yahoo.com/question/index?qid=20191022000038AA9EPLH
Tue, 22 Oct 2019 00:27:32 +0000
Use the distributive property.
(2x^2  5x + 1)(3x  1) =
2x^2(3x)  5x(3x) + 1(3x) + 2x^2(1)  5x(1) + 1(1) =
6x^3  15x^2 + 3x  2x^2 + 5x  1 =
6x^3  17x^2 + 8x  1

From ted s: the Distributive property yields (2x²)(3x) + (...
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https://au.answers.yahoo.com/question/index?qid=20191022000038AA9EPLH
Tue, 22 Oct 2019 00:07:11 +0000
the Distributive property yields (2x²)(3x) + (2x²)(1)  (5x)(3x)  ( 5x)(1) + (1) (3x) + (1)(1) = 6 x³ 2x²  15 x² + 5x + 3x  1 = 6 x³  17 x² + 8x  1

From IsaacM: PEMDAS Parenthesis first, then exponent. Then ...
https://au.answers.yahoo.com/question/index?qid=20191022000038AA9EPLH
https://au.answers.yahoo.com/question/index?qid=20191022000038AA9EPLH
Tue, 22 Oct 2019 00:05:03 +0000
PEMDAS Parenthesis first, then exponent. Then multiply, then divide. Add. Then subtract. 2x^2 is 4x. All the numbers with x are just equaling the solution plus x. They're all x.