Yahoo Answers: Answers and Comments for What is the value of A (physics)? [Physics]
Copyright © Yahoo! Inc. All rights reserved.
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
From Anonymous
enAU
Fri, 17 Jan 2020 23:57:50 +0000
3
Yahoo Answers: Answers and Comments for What is the value of A (physics)? [Physics]
292
38
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://s.yimg.com/zz/combo?images/emaillogoau.png

From Lôn: Easy.... it's 90  39.2 = 50.8.
sin (39.2...
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Sat, 18 Jan 2020 00:01:49 +0000
Easy.... it's 90  39.2 = 50.8.
sin (39.2) = 0.6320
cos (50.8) = 0.6320

From skeptik: The most straightforward way of remembering th...
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Sat, 18 Jan 2020 00:20:44 +0000
The most straightforward way of remembering things like this is to recall that these functions are all ratios involved in right triangles.
Sine = Opposite/Hypotenuse
Cosine = Adjacent/Hypotenuse.
Which means that for any given right triangle, where A and B are the two angles aside from the right angle, Sin(A) = Cos(B)
Also, since we know that the sum of all the internal angles of any triangle = 180 degrees, we know that the sum of A and B must be 90 degrees in a right triangle. In other words, they are complementary angles.
Combining all that previous knowledge together, we get Sin(A) = Cos(90A). The Sine of any acute angle is the Cosine of its complementary angle.
Plugging your numbers into it, we get:
Sin(39.2) = Cos(9039.2)
So the value of your answer is 9039.2 = 50.8

From Spaceman: sin 39.2° = 0.632029303
cos A = 0.632029303...
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Sat, 18 Jan 2020 20:55:16 +0000
sin 39.2° = 0.632029303
cos A = 0.632029303
A = arccos 0.632029
A = 50.8 °

From Anonymous: the easier way :
sin 39.20° = 0.6320
0.6320 = ...
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Sat, 18 Jan 2020 05:05:31 +0000
the easier way :
sin 39.20° = 0.6320
0.6320 = cos A
A = arccos 0.6320 = 50.80°

From billrussell42: sin(39.2)=cos(A)
cosA = 0.6320293
A = 50.8º
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Sat, 18 Jan 2020 00:00:18 +0000
sin(39.2)=cos(A)
cosA = 0.6320293
A = 50.8º

From yohanes: sin(39.2) = cos(A)
sin(39.2) = sin(A + 90)
(39...
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Fri, 24 Jan 2020 15:31:44 +0000
sin(39.2) = cos(A)
sin(39.2) = sin(A + 90)
(39.2) = (A + 90)
A = 50.8
www.physicstutorialroom.com

From oldschool: You can use a calculator to do this. Find the ...
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Tue, 21 Jan 2020 06:31:56 +0000
You can use a calculator to do this. Find the sine of 39.2° and then using the same calculator find the arcos of that. You will find that
A = 90°39.2° = 50.8° since sin(Θ) = cos(90Θ)

From Vaman: cos a=sin 39.2= cos (39.290)
a= 39.290=50.8
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
https://au.answers.yahoo.com/question/index?qid=20200117235750AAn43lo
Sat, 18 Jan 2020 07:12:30 +0000
cos a=sin 39.2= cos (39.290)
a= 39.290=50.8